By Je-Chin Han
Entrance disguise; Contents; Preface; bankruptcy 1. warmth Conduction Equations; bankruptcy 2. 1-D Steady-State warmth Conduction; bankruptcy three. 2-D Steady-State warmth Conduction; bankruptcy four. brief warmth Conduction; bankruptcy five. Numerical research in warmth Conduction; bankruptcy 6. warmth Convection Equations; bankruptcy 7. exterior compelled Convection; bankruptcy eight. inner pressured Convection; bankruptcy nine. typical Convection; bankruptcy 10. Turbulent stream warmth move; bankruptcy eleven. primary Radiation; bankruptcy 12. View issue; bankruptcy thirteen. Radiation trade in a Nonparticipating Medium.
Chapter 14. Radiation move via GasesAppendix A: Mathematical family and capabilities; again Cover. Read more...
summary: entrance conceal; Contents; Preface; bankruptcy 1. warmth Conduction Equations; bankruptcy 2. 1-D Steady-State warmth Conduction; bankruptcy three. 2-D Steady-State warmth Conduction; bankruptcy four. temporary warmth Conduction; bankruptcy five. Numerical research in warmth Conduction; bankruptcy 6. warmth Convection Equations; bankruptcy 7. exterior compelled Convection; bankruptcy eight. inner compelled Convection; bankruptcy nine. normal Convection; bankruptcy 10. Turbulent move warmth move; bankruptcy eleven. primary Radiation; bankruptcy 12. View issue; bankruptcy thirteen. Radiation alternate in a Nonparticipating Medium.
Chapter 14. Radiation move via GasesAppendix A: Mathematical kinfolk and capabilities; again hide
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Additional info for Analytical Heat Transfer
3. Determine heat loss per tube length as the following conditions: Given: Steam Inside the Pipe Air Outside the Pipe T∞1 = 250◦ C T∞2 = 20◦ C h1 = 500 W/m2 K Find: q/L =? 3. 6. The cylinder has a thin metal sheath and is immersed in a liquid at temperature T∞ . Heat transfer from the cylinder surface to the liquid can be characterized by a heat transfer coefficient h. Obtain the steady-state temperature distributions for the following cases: a. q˙ = q˙ o 1 − (r/ro )2 . b. q˙ = a + b(T − T∞ ). 4.
For example, we are interested in determining the temperature distribution in a 2-D rectangular block with appropriate BCs. Once the temperature distribution is known, the associated heat transfer rate can be determined. The following are the steady-state 2-D heat conduction equations without heat generation and the typical BCs with given surface temperatures. 2) Boundary conditions: x = 0, x = a, y = 0, y = b, T = 0 or x = 0, θ = 0 homogeneous BC T = 0 or x = a, θ = 0 homogeneous BC T = 0 or y = 0, θ = 0 homogeneous BC T = Ts or y = b, θ = Ts − T0 = θs nonhomogeneous BC Here, we defined a homogeneous BC as T = 0, or ∂T/∂x = 0, ∂T/∂y = 0; θ = 0, or ∂θ/∂x = 0, ∂θ/∂y = 0, that is, temperature or temperature gradient at a given boundary surface (in the x- or y-direction) equals 0.
A. Derive the heat conduction equation of disk. b. Determine the disk temperature distributions. c. Do you think the disk temperature is hotter at the center or the periphery? Why? 6. 9b, that is affixed to a tube. The inner and outer radii of the fin are ri and ro , respectively, and the thickness of the fin is t. , the base of the annular fin) is maintained at a temperature of Tb or T(ri ) = Tb . Both the top and the bottom surfaces are exposed to a fluid at T∞ . The convection heat transfer coefficient between the fin surfaces and the fluid is h.
Analytical Heat Transfer by Je-Chin Han